Thevenin Equivalents

Objective: our goal is to take a circuit with multiple voltage sources and resistors and calculate and test the Thevenin Equivalents

First we calculate Vth which is equal to Vx

then we Calculate the following,
Vy=5.11V
Vy/Rc3=Isc
Rth=Voc/Isc
Rth=65.98ohms

1.
then we find the smallest permissible RL2 using a voltage divider which is
Vth/(Rth+RL2)*RL2=VL2
VL2=8V
RL2=819.9ohms


2.
The short circuit current is then found by
8/819.9=.0098A


3.
The open circuit voltage is found to be
8.64V

then we set up the experiment

and come up with the following values

Component	Nominal Value	Measured Value
Rth	66Ω	65.9Ω
Rl2,min	819.9Ω	820Ω
Vth	8.64V	8.66V

Config	Theoretical Value	Measured Value	% Error
Rl2=Rl2,min	Vload2=8V	7.78V	2.75%
Rl2=infiniteΩ	Vload2=8.64V	8.71V	1.00%

Component	Nominal Value	Measured Value
Rc1	100	98
Rc2	39	38
Rc3	39	39
RL1	680	667
Vs1	9	9.1
Vs2	9	9.18

Config	Theoretical Value	Measured Value
Rl2=Rl2,min	Vload2=8V	6.9
Rl2=infiniteΩ	Vload2=8.64V	7.94

Configuration	Vload2
RL2=0.5Rth	1.8
RL2=Rth	2.85
RL2=2Rth	4.16

in conclusion we have found that by calculating the Thevenin Equivalents we can easily find new values for V and R thevenin when sources or resistors are added to the circuit.